## Exploration 6.5: Circular Motion and Work

v0x = m/s

A 1-kg black ball is constrained to move in a circle as shown in the animation (position is given in meters, time is given in seconds, and energy on the bar graph is given in joules). In the animation the wire is vertical and the ball is subjected to gravity (downward as usual), as well as the force of the wire. You may set the initial velocity and then play the animation. The blue arrow represents the net force acting on the mass, while the bar graph displays its kinetic energy in joules. Restart.

1. Set the speed fast enough to get the ball over the top. Then restart and examine forces at positions near, say, -45o and 45o (hanging straight down is -90o). Label your forces as Fg (gravity), Fwire, and Fnet.
2. Given your force diagrams, there are positions where the speed of the ball is changing more rapidly than others. Take each of the positions you considered and rank them from highest tangential acceleration to lowest.
3. Assume that the ball can get to y = 10 m. How much kinetic energy does the ball lose in going from y = -10 m to y = 10 m? Is this independent of v0x initial?
4. What is the work done by gravity when the ball goes from y = -10 m to y = 10 m?
5. Determine the minimum speed that the ball must have to go over the top. Once you have an answer, check it using the animation. Physlets were developed at Davidson College and converted from Java to JavaScript using the SwingJS system developed at St. Olaf College.

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